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-18x^2+47x+58=0
a = -18; b = 47; c = +58;
Δ = b2-4ac
Δ = 472-4·(-18)·58
Δ = 6385
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(47)-\sqrt{6385}}{2*-18}=\frac{-47-\sqrt{6385}}{-36} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(47)+\sqrt{6385}}{2*-18}=\frac{-47+\sqrt{6385}}{-36} $
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